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8x^2=3.2x
We move all terms to the left:
8x^2-(3.2x)=0
We add all the numbers together, and all the variables
8x^2-(+3.2x)=0
We get rid of parentheses
8x^2-3.2x=0
a = 8; b = -3.2; c = 0;
Δ = b2-4ac
Δ = -3.22-4·8·0
Δ = 10.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.2)-\sqrt{10.24}}{2*8}=\frac{3.2-\sqrt{10.24}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.2)+\sqrt{10.24}}{2*8}=\frac{3.2+\sqrt{10.24}}{16} $
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